Question

p( x) = x+3x square-1 and g(x)= 1+x

Answer 1

Hey friend---_____
here is your ans--------
$p(x) = x + 3x {2}^{} - 1 \\ g(x) = 1 + x \\ let \:1 +x = 0 - \\ x = - 1 \\ put \: the \: value \: of x in the \: given \: poylynomial \\ ( - 1) + 3( - 1 {}^{2} ) - 1 \\ = - 1 + 3 - 1 \\ = 1$Hope it help-----______---