Question

P(X) = x^4-2x^3+3x^2-ax+3a-7
When divided by (X+1), leaves the remainder 19, find the value of a. Also, find the remainder, when p(X) is divided by (X+2).

Answer 1

Answer:

x^4-2x^3+3x^2-ax+3a-7

put x+1=0

x=-1

p(x)=4(-1)^4-2(-1)^3+3(-1)^2-a(-1)+3a-7=19

4+2+3+a+3a-7=19

6+4a-7=19

-1+4a=19

4a=20

a=5

p(x)=x^4-2x^3+3x^2-ax+3a-7

put x+2=0

×=-2

p(-2)=(-2)^4-2(-2)^3+3(-2)^2-5(-2)+3(5)-7=0

16+16+12+10+15-7=0

69-7=0

62

Answer 2

Step-by-step explanation:

p(-1)=(-1)⁴-2(-1)³+3(-1)²-a(-1)+3(a)-7

19 =1+2+3+a+3a-7

19=6-2a-7

19=4a-1

20=4a

a=20/4

a=5

p(x)=x⁴-2x³+3x²-5x+8

p(-2)=(-2)⁴-2(-2)³+3(-2)²-5(-2)+8

=16+16+12+10+8

=62

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