Question

P(x)=x^4-6x^3-26x^2+138x-35 zeroes are 2x+root 3

Answer 1

Answer:

The two zeroes of the polynomial is 2+

3

,2−

3

Therefore, (x−2+

3

)(x−2−

3

)=x

2

+4−4x−3

= x

2

−4x+1 is a factor of the given polynomial.

Using division algorithm, we get

x

4

−6x

3

−26x

2

+138x−35=(x

2

−4x+1)(x

2

−2x−35)

So, (x

2

−2x−35) is also a factor of the given polynomial.

x

2

−2x−35=x

2

−7x+5x−35

=x(x−7)+5(x−7)

=(x−7)(x+5)

Hence, 7 and −5are the other zeros of this polynomial.

If u didn't understood then u can see the Attachment above.

I hope it helps!!