Question

p(x)=x^6+x^4-x^2-1:g(x)=x³-x²+x-1​

Answer 1

Answer:

Step-by-step explanation:

Given p(x) = x³-x²+x+1

so, p(1) = (1)³-(1)²+1+1 = 2.

and p(-1) = -1-1+1+1 = 0

therefore , p(1)+p(-1) = 2+0 = 2. and

{p(1)+p(-1)}/2 = 2/2 = 1.