Question

p(X)=X+9 find the zeros of the polynomial​

Answer 1

p(x)=x^2-9

p(x)=x^2-3^2

using identity a^2-b^2=(a+b)(a-b)

p(x)=(x+3)(x-3)

The zeroes of the polynomial are: -3 and 3

Answer 2

Answer:

p(x)=x+9

x=-9

zero of polynomial is -9