Question

p(x) =x square +2 √2x-6 find the zeroes of the quadratic polynomial​

Answer 1

Answer:

Hence, the zeros of the quadratic equation are √2 and -3√2.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

p(x) = x2 + 2√2x – 6

We put p(x) = 0

⇒ x2 + 2√2x – 6 = 0

⇒ x2 + 3√2x – √2x – 6 = 0

⇒ x(x + 3√2) – √2 (x + 3√2) = 0

⇒ (x – √2)(x + 3√2)

= 0 This gives us 2 zeros, for x

= √2 and x = -3√2

Hence, the zeros of the quadratic equation are √2 and -3√2.

Now, for verification

Sum of zeros = –coefficientofxcoefficientofx2–coefficientofxcoefficientofx2 √2 + (-3√2) = – (22√)1(22)1 -2√2 = -2√2

Product of roots = constantcoefficientofx2constantcoefficientofx2 √2 x (-3√2) = (−6)22√(−6)22 -3 x 2 = -6/1 -6 = -6

Therefore, the relationship between zeros and their coefficients is verified.