Question

p(x)=x square -4 find the zero of polynomial.​

Answer 1

Answer:

$\large{\underline{\boxed{\sf 2 \: \: and \: \: (-2)}}}$

Step-by-step explanation:

Given that ;

p(x) = x² - 4

⇒ x² - 4 = 0

⇒ x² = 4

⇒ x = ±√4

⇒ x = ±2

Hence, the zeroes of the polynomial is 2 and (-2).

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Verification:

Sum of zeroes = $\sf - \dfrac{b}{a}$

⇒ 2 - 2 = 0/1

⇒ 0 = 0

Product of zeroes = $\sf \dfrac{c}{a}$

⇒ 2 * (-2) = - 4/1

⇒ - 4 = - 4

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Hence, the zeroes of the polynomial are (2) and (-2).

Answer 2

Answer:

2 and ( -2 )

Step-by-step explanation:

Given,

p ( x ) = x² - 4

= x² - 4 = 0

= x² = 4

= x = ± √4

= x = ± 2

Hence, the zeroes of the polynomial is 2 and ( -2 ).

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Verification:

Sum of zeroes = $\huge{\frac{b}{a}}$

= 2 - 2 = 0/1

= 0 = 0

Product of zeroes = $\huge{\frac{c}{a}}$

= 2 × ( -2 ) = -4/1

= -4 = -4

Hence, the zeroes of the polynomial are 2 and ( -2 ).

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Hope it is helpful.....