Question

p(x)=x square- 5x-6 then find values of p(1),p(2),p(3).

Answer 1

Hey !!!

p(x ) = x² - 5x - 6

p( 1 ) = 1² - 5 ( 1) - 6

=> 1 - 5 - 6

=> -10

p(1) = 0 Answer ✔

p(2) = (2)² - 5 ( 2) - 6

p(2) = 4 - 10 - 6

p(2) = -12

p(3) = ( 3)² - 5(3) - 6

p(3) = 9 - 15 - 6

p(3) = 9 - 21= 0

p(3) = - 12
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Hope it helps you !!

@Mr.rajukumar111

Answer 2

hey dear here is your answer


p(x) = x*2 -5x -6

so p(x)= 1


p(1) = (1)*2-5(1)-6

p(1) = 1-5-6

p(1)= 1-11

p(1) = -10


p(2)

p(2)= x2 -5x-6

p(2) = (2)*2 -5(2)-6

p(2)= 4-10-6

p(2) = 4-16

p(2)= -12

p(3)= x2-5x-6

p(3) = (3)2 -5(3)-6

p(3) = 9-15-6

p(3) = 9-21


p(3) = -12


hope helps you