Question

p(x) = x² – 1,x= 1, -1​

Answer 1

Answer:

LET P(x) = x²-1

put x= 1

=> p(1) = (1)²-1

= 1-1

= 0

At p(1) =0

now put x = -1

=> p(-1) = (-1)²-1

= 1-1

= 0

At p(-1) = 0

Hence , 1 and -1 are both the zero's of polynomial.

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