Question

p (x) = x²-1, x = 1 , -1​

Answer 1

Answer:

$p(x) = {x}^{2} - 1 \\ = {x}^{2} - {1}^{2} \\ = (x - 1)(x + 1) \\ if \: p(x) = 0 \: then \\ x = 1 \: or \: - 1 \: \\ ( \frac{ + }{} 1 \: in \: standard \: form)$

Answer 2

Answer:

Answer is 0

Step-by-step explanation:

$x = 1 \\ x + 1 = 0 \\ x = 0 - 1 \\ x = - 1 \\ \\ p(x) = x {}^{2} - 1 \\ p( - 1) = ( - 1) {}^{2} - 1 \\ = 1 - 1 = 0 \\ \\ \\ x = - 1 \\ x - 1 = 0 \\ x = 0 + 1 \\ x = 1 \\ \\ p(x) = x {}^{2} - 1 \\ p(1) = (1) {}^{2} - 1 \\ = 1 - 1 \\ = 0$

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