p(x) = x²=1, x=1, -1
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Shade the area of the region bounded by, x2 + y2 sp2 and 1x1 + lyl 2 p Hence, find the area of the specified region using integration. The base of a solid is the region between the curve, y?(p + x) = x²(3p – x),0 SX S3p, y = 0 and the X - axis. If the cross-sections perpendicular to the x-axis are equilateral triangles with bases running from the x-axis to the given curve, find the volume of the solid obtained.
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p(x) =1^2+1-1
p(x)1+1-1
,there fore p(x) is 1
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