Question

P ( x ) = x² + 2√2 x - 6.​

Answer 1

Answer:

${x}^{2} + 2 \sqrt{2} - 6 = 0$

${x}^{2} + 3 \sqrt{2} x - \sqrt{2} x - 6 = 0$

$x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) = 0$

Therefore,

$(x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0$

$x = \sqrt{2} \: or \: x = - 3 \sqrt{2}$