P(x)=x²-2√2x+1; find p(3√2)
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Solution:
p(x) = x²-2√2x+1
Put x = 3√2 ,
Value of p(3√2)
= (3√2)²-2√2(3√2)+1
= 18 - 12 + 1
= 6 + 1
= 7
Therefore,
p(3√2) = 7
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