p(x)=x²-2√2x+1,then find value of p(2√2)
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Answer:p(2^2)=5
Explanation:
given,
p(x)=x^2-√2x+1
therefore,
p(2√2)=(2√2)^2-√2×2√2+1
=4×2-2×2+1, [√2×√2=2]
=8-4+1
=8-3
=5
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