Math, asked by rockingtanveer2005, 11 months ago

p(x)=x²-2√2x+1,then find value of p(2√2)​

Answers

Answered by Abhilash210
4

Answer:p(2^2)=5

Explanation:

given,

p(x)=x^2-√2x+1

therefore,

p(2√2)=(2√2)^2-√2×2√2+1

=4×2-2×2+1, [√2×√2=2]

=8-4+1

=8-3

=5

Here's your answer.I hope it will help you

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