Question

p(x)=x²-2√2x+1,then p (2√2) is equal to​

Answer 1

Answer:

1

Step-by-step explanation:

p(x) = x²-2√2x+1

p(2√2) = (2√2)²-2√2(2√2)+1

            = 4(2)-4(2)+1

            = 0+1

p(2√2) = 1

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Answer 2

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GIVEN :-

$p(x) = x {}^{2} - 2 \sqrt{2} x+ 1$

TO FIND :- P(2root2)

SOLUTION: -

$p(2 \sqrt{2} ) = (2 \sqrt{2} ) {}^{2} - 2 \sqrt{2} (2 \sqrt{2} ) + 1$

$= 4(2) - 4(2) + 1$

=0+1

=1.

HOPE IT HELPS :)