P(x) = x² +2√2x - 6
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Answer:
-6
Step-by-step explanation:
p(x) = x2 + 2√2x – 6
We put p(x) = 0
⇒ x2 + 2√2x – 6 = 0
⇒ x2 + 3√2x – √2x – 6 = 0
⇒ x(x + 3√2) – √2 (x + 3√2) = 0
⇒ (x – √2)(x + 3√2) = 0
This gives us 2 zeros,
for x = √2 and x = -3√2
Hence, the zeros of the quadratic equation are √2 and -3√2.
Now, for verification
Sum of zeros = –coefficient of x/–coefficient of x2
√2 + (-3√2) = – (22√)1(22)/1
-2√2 = -2√2
Product of roots = constant/coefficientofx2 √2 x (-3√2) = (−6)22√(−6)22
-3 x 2 = -6/1 -6 = -6
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