P(x)=x2+2root2x-6.. find the zero of polynomial
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p(x) = x² + 2√2x - 6
We can find the zeros by factorization [ by splitting the middle terms ]
x² + 2√2x - 6
x² + 3√2x - √2x - 6
x [ x + 3√2 ] - √2 [ x+ 3√2]
[ x - √2 ] [ x+ 3√2]
the zeros are = √2 and -3√2
Read more on Brainly.in - https://brainly.in/question/1257513#readmore
p(x) = x² + 2√2x - 6
We can find the zeros by factorization [ by splitting the middle terms ]
x² + 2√2x - 6
x² + 3√2x - √2x - 6
x [ x + 3√2 ] - √2 [ x+ 3√2]
[ x - √2 ] [ x+ 3√2]
the zeros are = √2 and -3√2
Read more on Brainly.in - https://brainly.in/question/1257513#readmore
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