Math, asked by vamvamtut262, 10 months ago

P(x)=x2+2x-3 then find p(√2)

Answers

Answered by honet137
1

Step-by-step explanation:

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Answered by mysticd
1

 Given \:p(x) = x^{2} + 2x - 3

 Value \: of \:p(\sqrt{2} \\= (\sqrt{2})^{2} + 2(\sqrt{2} - 3 \\= 2 + 2\sqrt{2} - 3 \\= 2\sqrt{2} - 1

Therefore.,

 \red {Value \: of \:p(\sqrt{2}}\green {= 2\sqrt{2} - 1}

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