Question

p(x)=x²-2x-8 find the zeroes sum of zeroes and product of zeroes​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$x {}^{2} - 2x - 8 = 0 \\ x {}^{2} + 2x - 4x - 8 = 0 \\ x(x + 2) - 4(x + 2) = 0 \\ (x - 4)(x + 2) = 0 \\ x = 4 \: and \: - 2 \\ sum = - 2 + 4 = 2 \\ product = - 2 \times 4 = - 8$