Question

P(x) = x²-3 then alpha+beta =​

Answer 1

Answer:

alpha + beta= 0..... here is your answer

Answer 2

$Given \: p(x) = x^{2} - 3$

$If \: \alpha \: and \: \beta \: are \: two \: zeroes$

$of \: the \: Quadratic \: polynomial \:then$

$\alpha + \beta = \frac{ Coefficient \: of \: x }{Coefficient \: of \: x^{2}}$

$= \frac{0}{1}$

$= 0$

Therefore.,

$\green {\alpha + \beta }\green { = 0 }$

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