Question

p(x)=x2-3x+2 find the p(0) p(1) p(2)​

Answer 1

Answer:

Hey mate!

Here's your answer.

Given polynomial is p(x)=x

2

−3x+2

Replace x by 0, we get

p(0)=(0)

2

−3(0)+2

⇒p(0)=0+0+2

⇒p(0)=2

Replace x by 1, we get

p(1)=(1)

2

−3(1)+2

⇒p(1)=1−3+2

⇒p(1)=0

Replace x by 2, we get

p(2)=(2)

2

−3(2)+2

⇒p(2)=4−6+2

⇒p(2)=0

Hope that it helps you plz mark as brainliest.

Answer 2

Answer:

p(0)=2

p(1)=0

p(2)=0

hope it help you