Question

P(x) = x²-3x+2 find the polynomial​

Answer 1

Answer:

he zeros of polynomial p(x)=x  

2

−3x+2 can be given y p(x)=0

⟹x  

2

−3x+2=0

x  

2

−2x−x+2=0

x(x−2)−1(x−2)=0

(x−1)(x−2)=0

x=1,2

Step-by-step explanation:

Answer 2

ANSWER

->${x}^{2} - 3x + 2 = 0$

->${x}^{2} - 2x - x + 2 = 0$

->$x(x - 2) - 1(x - 2) = 0$

-->$(x - 1)(x - 2) = 0$

-->$x = 1$

-->$x = 2$

x=1,2 is your answer

Hope it helps you

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