Question

p(x)=x²-3x+2 x=1,x=0,x=2​

Answer 1

Answer:

The zeros of polynomial p(x)=x2−3x+2 can be given y p(x)=0

⟹x2−3x+2=0

x2−2x−x+2=0

x(x−2)−1(x−2)=0

(x−1)(x−2)=0

x=1,2