Question

P (x)=x2-4 then verify that 2 and -2 also the zero of p (x )

Answer 1

Answer:

$p(x) = {x}^{2} - 4 \\ when \: x = 2 \\ p(x) = {2}^{2} - 4 = 4 - 4 = 0 \\ and \: when \: x \: = - 2 \\ p(x) = {( - 2)}^{2} - 4 = 4 - 4 = 0$