p(x)=x²-4x+4,evaluate p(2)-p(-1)
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Answer:
p(x) =x^2-4x+4
put x=2in given equation, we get
p(2) =2^2-4(2) +4
p(2) =4-8+4
p(2) =8-8
p(2) =0.
put x=-1 in given equation, we get
p(x) =x^2-4x+4
p(-1) =(-1) ^2-4(-1) +4
p(-1) =1+4+4
p(-1) =9.
put p(2) =0 and p(-1) =9 we get
p(2)-p(-1)
0-9=-9 ans
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