Question

p(x)=x2-4x+5 given polynomial find the zeros​

Answer 1

x²- 4x +5

x² -5x -x +5. ( by factorisation method)

x(x-5) -1( x -5)

hence = (x-1) , (x-5)

zeroes , x =5 ,

x =1

Answer 2

The given question is p(x)=

${x}^{2} - 4x + 5$

find the zeroes for given polynomial

The formula to find the roots or zeroes of the given polynomial is

$\frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a}$

here a=1, b=-4, c=5

substitute these values in the equation, we get

$\frac{ - ( -4 ) + - \sqrt{( { - 4)}^{2} - 4(1)(5)} }{2(1)} \\ \frac{4 + - \sqrt{16 - 20} }{2} \\ \frac{4 + - \sqrt{ - 4} }{2} \\ \frac{2 + - 2i}{2} \\ = \frac{2(1 + - i)}{2} \\ (1 + i)(1 - i)$

Therefore, the final answer is (1+i) (1-i)

The zeroes are imaginary here.

# spj2

we can find the simialr question through the link

https://brainly.in/question/16705699?referrer=searchResults