Question

p(x)=x2-4x+5 given polynomial find the zeros and graph​

Answer 1

Step-by-step explanation:

x2-4x+5=0

x2+1x-5x+5

x(x+1)-5(x+1)=0

(x-5)(x+1)=0

x-5=0,x+1=0

x=5,x=-1

Answer 2

x^2-4x+5

by using quadratic formula

a=1,b=-4,c=5

QUADRATIC FORMULA=-b+-√b^2-4ac) / 2a

-(-4)+-[root over (-4)^2-4*1*5]/2*1

[4+-[root over 16-20]]/2

[4+-r-4]/2

r=root over

the zeroes are

(4+r-4)/2

(4-r-4)/2

ACTUALLY THESE COMES UNDER IMAGINARY ROOTS