P(x) x²-5√5x + 5 then P(5√5) = ?
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Answer:
given, P(x)=x^2-5root5.x+5.
then find, p(5root5)
let p(x) be the equation 1
put the value,x=5root5 in(1)
p(5root5)= (5root5)^2-5root5×5root5+5
so, 5root5×5root5= 125
therefore, = 125-125+5
=0+5
=5 ans.
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