Question

P(x) x²-5√5x + 5 then P(5√5) = ?​

Answer 1

Given: $p(x)=x^{2} -5\sqrt{5}x+5$

To find: $p(5\sqrt{5} )$

Step-by-step explanation:

$p(x) = x^{2} -5\sqrt{5}x+5\\ p(5\sqrt{5})= (5\sqrt{5})^2-5\sqrt{5}(5\sqrt{5})+5\\ p(5\sqrt{5})= 125-125+5\\ p(5\sqrt{5)}= 5$