Question

p(x)=x2-5x-6 find the value of p(1),p(2),p(3),p(0),p(-1),p(-2)p(-3)​

Answer 1

Answer:

p(1)=-10

p(2)=-12

p(3)=-12

p(0)=-6

p(-1)=0

p(-2)=8

p(-3)=18

Step-by-step explanation:

Hope it helps you ❤

Answer 2

Answer:

p(1)=1×2-5×1-6

=2-5-6

=-9

p(2)=2×2-5×2-6

=4-10-6

= -12

p(3)=3×2-5×3-6

=6-15-6

=15

p(0)=0×2-0×5-6

=-6

p(-1)=-1×2-5×-1×-6

=-2+5-6

-3

p(-2)=-2×2-5×-2-6

= -4 +10-6

=0

p(-3)=-3×2-5×-3-6

= -6+15-6

= 3

Step-by-step explanation:

..I know but in places of x u need to put those given no ...then u should do multiple cation