Math, asked by kehkashabegum69082, 1 year ago

P(x)=x2-5x-6 find the value of p(1),p(2),p(3),p(0),p(-1),p(-2),p(-3).

Answers

Answered by dishagaur748

130

hey mate!!

p(x)=x^2-5x-6

p(1)=1^2-5(1)-6
=1-5-6
=-4-6
=-10

p(2)=2^2-5(2)-6
=4-10-6
=-6-6
=-12

p(3)=3^2-5(3)-6
=9-15-6
=-6-6
=-12

p(0)=0^2-5(0)-6
=-6

p(-1)=-1^2-5(-1)-6
=1+5-6
=0

p(-2)=-2^2-5(-2)-6
=4+10-6
=14-6
=8

p(-3)=-3^2-5(-3)-6
=9+15-6
=24-6
=18

hope it helps!!

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Answered by cchinni64

may this ans helps u...

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