Math, asked by srmt9559, 3 months ago

p(x) = x2 – 5x - 6, find the values of p(1),p(2), p(3), p(0),p(-1),p(-2), p(-3).​

Answers

Answered by sreyarani281
0

Answer:

p(-1)

Step-by-step explanation:

p(x)=x

2

−5x−6

p(1)=1

2

−5(1)−6=1−5−6=−10

p(2)=2

2

−5(2)−6=4−10−6=−12

p(3)=3

2

−5(3)−6=9−15−6=−12

p(0)=0

2

−5(0)−6=0−0−6=−6

p(−1)=(−1)

2

−5(−1)−6=1+5−6=0

p(−2)=(−2)

2

−5(−2)−6=4+10−6=8

p(−3)=(−3)

2

−5(−3)−6=9+15−6=18

Answered by freepdfindiaengineer
0

Answer:

p(1)=-10

p(2)=-12

p(3)=-12

p(0)=-6

p(-1)=0

p(-2)=8

p(-3)=18

Similar questions