Question

p(x) = x²-7x+10 find p(-1/2) ​

Answer 1

Step-by-step explanation:

Given quadratic polynomial x2 + 7x + 10

Using factorisation (splitting the middle term)

x2 + 7x + 10 = 0

x2 + (5x + 2x) + 10 = 0

x2 + 5x + 2x + 10 = 0

x(x + 5) + 2 (x + 5) = 0

(x + 5) (x + 2) = 0

Hence, zeroes of a given quadratic polynomial are – 5 and – 2.

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient