Question

p(x)=x2-9x+26 find the zero of the polynomial and make relationship with its coefficients.​

Answer 1

p(x)=x2-9x+26

Relationship between zeroes and coefficients

Sum of zeroes=-(coefficient of x)/coefficient of x^2=-(-9)/1=9

Product of zeroes=constant term/coefficient of x^2=26/1=26

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Answer 2

Answer:

$\\ = x^2-4x-5x+20\\= x(x-4) (x-5)=0\\= (x-4) = 0\\= x = 4\\= \alpha = 4\\= x-5 =0\\= (x-5)\\= \beta =5$

=> Sum of Zeroes

= 4 + 5 = 9

=> Product of Zeroes

= 4 x 5 = 20

$= x^2 -9x +20\\= ax^2 -9x+20\\= ax^2 +bx+c\\= a=1, b=-9,c=20$

= ∝+β = -b/a

= ∝+β = -(9/9) = 9/1 = 9

= ∝β = c/a

= ∝β = 2-/1 = 20