p(x) = x² find p(0), p(1), p(2)
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1
Answer:
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Answered by
2
Answer:
p(x)=x2
−x+1
∴p(2)=2
2
−2+1=3
[replacing x by 2]
p(1)=1
2
−1+1=1
[replacing x by 1]
p(0)=(0)
2
−(0)+1=1
[replacing x by 0]
hope it helps
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