Question

p(x) = x² _kx+9 is 8.
K=8
x2 - (sum of the zeroes) x+(sum
product of Zeroes
​

Answer 1

Step-by-step explanation:

In a general quadratic equation of form ax ²+bx+c=0, sum of roots are by -b/a

In the given quadratic equation, x²-kx+9=0

a=1,b=-k,c=9

Sum of roots =-b/a=-(-k)/1=k

and sum of roots is given 8

k=8