Question

p(x)=x²+x-1 find the zeroes of the polynomial​

Answer 1

Step-by-step explanation:

Given a and ẞ are zeroes of the polynomial f(x) = ax2 + bx + c

a+ B = -b/a

aß = c/a.

If a and ẞ are zeroes of the quadratic polynomial p(x)=x2-(k-6)x+(2k+1) and a+B= aßa+ B = k - 6 and aß = 2k + 1

Given that a + B = aß

k-6=2k +1

.. k = -7.

Hope it helps!

Answer 2

Answer :

$= p(x)={x}^{2}x </p><p>2 -1$

$Let p(x) = 0$

Then,

$={x}^{2}x 2</p><p> -1 = 0$

$= {x}^{2}x$

$= x = \pm± 1$

•°• The zero of the polynomial is 1.

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