Question

p(x)=x2+x+k please answer my question​

Answer 1

Step-by-step explanation:

sir here is ur answer

let p(x)= -1, -2 and 1,2

let the p(x)=-1

=X2+x+k

=

${ - 1}^{2 } +( - 1) + k$

1 - 1 + k

0 + k then k=0

let the p(x)=-2

x2 +x+k

(-2)+(-2)+k

-2+2+k=0

0+k=0

then zero goes to another side

k=0

let p(x)=1

${1}^{2} + 1 + k \\ \\ 1 + 1 + k = 0 \\ 2 + k = 0 \\ k = - 2$

let p(x)=2

${2 }^{2} + 2 + k = 0 \\ 4 + 2 + k = 0 \\ 6 + k = 0 \\ k = - 6$