Question

P(x)=x2+x+kP(x)=x2+x+kP(x)=x2+x+k

Answer 1

Answer:

According to the Question

p(x) = kx² - 3x + k

If (x - 1) is a factor of p(x)

Therefore

x - 1 = 0

x = 1

Substitute the value of x in Equation

⇒ k(1)² - 3 × 1 + k = 0

⇒ 2k - 3 = 0

⇒ 2k = 3

⇒ k = \bf\huge\frac{3}{2}23

Answer 2

Answer:

P(x)=x2+x+kP(x)=x2+x+kP(x)=x2+x+k