Question

P(x) = x²+x²x+ 제 P(-2)= ? | p (=)) = ? 2​

Answer 1

Answer:

Step-by-step explanation:

It is given that p(x) = p(x) = x² - 6x + 8. To find a specific value of x, we substitute the value of x into the equation and solve the equation.

Given:

p(x) = x² - 6x + 8

Find the value of p(x) when x = 2:

p(x) = x² - 6x + 8

p(2) = (2)² - 6(2) + 8

p(2) = 4 - 12 + 8

p(2) = 0

Find the value of p(x) when x = -2:

p(x) = x² - 6x + 8

p(-2) = (-2)² - 6(-2) + 8

p(-2) = 4 + 12 + 8

p(-2) = 24

Answer: p(2) = 0 and p(-2) = 24