Question

p(x) = √x³ + 1 is not a polynomial. Give reason.​

Answer 1

Step-by-step explanation:

√x³ + 1 is also not a polynomial, since the exponents of variable in 1st term is a rational number.

Polynomial must be a mathematical expression of one or more algebraic terms each of which consists of a constant multiplied by one or more variables raised to a nonnegative integral power (such as a + b*x + cx2)

Answer 2

Answer:

p(x) = √x³ + 1 is not a polynomial

Step-by-step explanation:

A polynomial equation is an equation formed with variables, exponents, and coefficients together with operations and an equal sign. The general form of a polynomial equation is

$P(x) = a_{n} x^{n} +a_{n-1} x^{n-1}+a_{n-2} x^{n-2}+........+a_{2} x^{2}+a_{1} x^{1}+a_{0}$

p(x) = √x³ + 1 is not a polynomial.

As per the definition of polynomial, the power of a variable term is always a positive integer. But here the power of x is 3/2, which is clearly not an integer. So, p(x) is not a polynomial function.

hence p(x) = √x³ + 1 is not a polynomial

#SPJ2