Question

p(x ) x³ + 3x² + 2x +1 , g ( x ) x+2​

Answer 1

Given:

Remainder is given g(x)=x+2

p(x) is also given = x^3+3x^2+2x+1

To Find:

The value of x

Solution:

g(x)=x+2 =0

•x=-2

p(x)=x^3+3x^2+2x+1

Now put the value of xhere

•(-2)^3+3(-2)^2+2(-2)+1

•-8+12+(-4)+1

•-8+12-4+1

•-12+12+1

•1

Hence,the value of p(x) is 1.

Answer 2

Given:-

• p(x) = x³ + 3x² + 2x + 1
• g(x) = x + 2

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To Find:-

• The value of p(x).

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Solution:-

According to the question,

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⇢ p(x) = x³ + 3x² + 2x + 1

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• Putting x = -2

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⇢ (-2)³ + 3(-2)² + 2(-2) + 1

⇢ -8 + 12 + (-4) + 1

⇢ -8 + 12 - 4 + 1

⇢ -12 + 12 + 1

⇢ 1

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Hence,

• the value of p(x) is 1.