Math, asked by parshotam1975, 5 months ago

P(x) =x3+3x2-2x+4 find value of p(-2) +p(-1) plaese solve fast ​

Answers

Answered by 03pranay
1

Answer:

P(-2) = -10 and P(-1) = -3

Step-by-step explanation:

P(x) = x3+3x2-2x+4

P(x) = x3+3x2-2x+4P(-2) = (-2)3+3(-2)2-2(-2)+4

P(x) = x3+3x2-2x+4P(-2) = (-2)3+3(-2)2-2(-2)+4P(-2) = -6 -12 +4+4

P(x) = x3+3x2-2x+4P(-2) = (-2)3+3(-2)2-2(-2)+4P(-2) = -6 -12 +4+4 P(-2) = -18 +8

P(x) = x3+3x2-2x+4P(-2) = (-2)3+3(-2)2-2(-2)+4P(-2) = -6 -12 +4+4 P(-2) = -18 +8P(-2) = -10

P(x) = x3+3x2-2x+4

P(x) = x3+3x2-2x+4P(-1) = (-1)3+3(-1)2-2(-1)+4

)+4P(-1) = -3 -6 +2 +4

P(-1) = -9 + 6

P(-1) = -3

Similar questions