p(x)=x3-3x2-2x+6 at x=√2
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5
5√2+6
(√2)3-3√2*2-2√2+6
3√2-6√2-2√2+6
(√2)3-3√2*2-2√2+6
3√2-6√2-2√2+6
Answered by
11
Hi ,
P( x ) = x³ - 3x² - 2x + 6
If x = √2 ,
P( √2 )= ( √2 )³ - 3 ( √2 )² - 2( √2 ) + 6
= 2√2 - 6 - 2√2 + 6
= 0
I hope this helps you.
: )
P( x ) = x³ - 3x² - 2x + 6
If x = √2 ,
P( √2 )= ( √2 )³ - 3 ( √2 )² - 2( √2 ) + 6
= 2√2 - 6 - 2√2 + 6
= 0
I hope this helps you.
: )
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