Question

p ( x ) = x³ + 3x² + 3x + 1
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Answer 1

Answer:

6X^2 + p^3

Hope it helps to u

Hope it helps to u

Answer 2

Roots of this polynomial are -1,-1,-1.

Step-by-step explanation:

Step 1 - To find the first root of given polynomial

we are given

p(x) = x³ + 3x² + 3x + 1

let x = -1 and find p(-1) which we get,

p( -1) = (-1)³ + 3(-1)² + 3(-1) + 1 = -1 +3-3 +1 = 0

p (-1) =0 it means we get our first root for this polynomial is -1 or we get (x+1).

Step 2 - Divide given polynomial with ( x + 1)

Divide p(x) with ( x + 1) by using Remainder theorem to get other 2 roots . By dividing x³ + 3x² + 3x + 1 with (x+1). By using Reminder theorem we get zero remainder and a quadratic equation x² + 2x + 1 as quotient . we can solve this quadratic equation and get other two roots. this quadratic is simply the answer of $(x + 1)^{2}$ so the other roots of p(x) polynomial are -1,-1.

so our three roots of this p(x) polynomial are -1,-1,-1.