Question

P(x)=x3+3x2+3x+1 g (x)=x+1

Answer 1

Answer:

step 1:

Division=0

x+1=0

x=-1

step 2:

Let p(x)=x3+3x2+3x+1

putting x=-1

p(-1)=(-1)3+3(-1)2+3(-1)+1

=-1+3-3+1

=0

Thus,remainder=p(-1)=0