Question

P(x) = x³ + 3x²+ 3x +1
substituting x=0 in p(x)​

Answer 1

Answer:

p(0) =0^3+3x0^2+3x0+1

=0+0+0+1

=1

Answer 2

Answer:

1

Step-by-step explanation:

p( x) =

${x}^{3} + 3 {x}^{2} \: + 3x + 1 \\ (0 {)}^{3 } + 3(0 {)}^{2} + 3(0) + 1 \\ 0 + 3(0) + 0 + 1 \\ 0 + 0 + 0 + 1 \\ = 1 \: ans.$

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