P(x)=(x³+3x²-4x+5) (x-1)
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(x-1) is not the factor of (x^3+x^2-4x+5)
as:x-1=0
x=1
now put in equation.
(1)^3+3×(1)^2-4×1+5
1+3-4+5
5≠0
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