Math, asked by Vanko, 11 months ago

P(x)=(x³+3x²-4x+5) (x-1)

Answers

Answered by Krissh56
0

(x-1) is not the factor of (x^3+x^2-4x+5)

as:x-1=0

x=1

now put in equation.

(1)^3+3×(1)^2-4×1+5

1+3-4+5

5≠0

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