Question

p(x)=x³ For the given polynomial, find p(1), p(0) and p(- 2).

Answer 1

Hey..!!
when we put x=0
p (0)=(0)^3 =0
p (1)= (1)^3 = 1
p (-2)= (-2)^3 = -8..

Hope this helps you....

Answer 2

Hey Mate,

Here Is Your Answer

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$If \: p(x)={x}^{3} \\ \\ then \: we \: have \: to \: find \: p(1) \\ \\ now \: for \: finding \: p(1) \\ \\ we \: assume \: p(x) = p(1) \\ \\ therefore \: \\ p(1) = {1}^{3} \\ p(1) = 1$


Similarly,You Can Find p(0) & p(-2) Also.

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Hope It Helps You.