Math, asked by bhagath21, 3 months ago

p(x) = x3 – x2 + x + 1 when x = 0, x =1​

Answers

Answered by sharvanikulkarni
1

Step-by-step explanation:

when x=0

p(0) = 0³-0²+0+1= 1

p(1)= 1³-1²+1+1 = 2

Answered by Anonymous
2

Answer:

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x3-x2+x+1

(0)3-(0)2+(0)+1

0-0+0+1

x=1

x3-x2+x+1

(1)3-(1)2+(1)+1

1-1+1+1

x=2

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